Arithmetic Aptitude - Problems On Age - Discussion
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Q. | Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age? |
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Answer: | Option A | |
Explaination: |
Let the present ages of sameer and anand be 5x years and 4x years respectively. Then 5x+3/4x+3=11/9 ![]() x=6. Anands's present age = 4x =24 years. |
Discussion
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