C - Pointers - Discussion

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Q.

main()

{
int c[ ]={2.8,3.4,4,6.7,5};
int j,*p=c,*q=c;
for(j=0;j<5;j++) {
printf(" %d ",*c);
++q; }
for(j=0;j<5;j++){
printf(" %d ",*p);
++p; }
}
A. 2 2 8 3 4 4 6 7 5 B. 2 2 2 2 2 3 4 6 5
C. 2 3 4 6 5 8 8 8 8 D. 2 2 2 2 2 2 3 5 7

Answer: Option B
Explaination:

Initially pointer c is assigned to both p and q. In the first loop, since only q is incremented and not c , the value 2 will be printed 5 times. In second loop p itself is incremented. So the values 2 3 4 6 5 will be printed.



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