Q. | What will be output of following c program? #include
int *call();
void main(){
int *ptr;
ptr=call();
fflush(stdin);/div>
printf("%d",*ptr);
}
int * call(){
int x=25;
++x;
return &x;
}
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Answer: | Option D | |
Explaination: | variable x is local variable. Its scope and lifetime is within the function call hence after returning address of x variable x became dead and pointer is still pointing ptr is still pointing to that location. |
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