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Q.

What will be output if you will execute following code?

#include
void main(){
long array[][3]={7l,14l,21l,28l,35l,42l};
long int (*ptr)[2][3]=&array;
printf("%li",-0[1[0[ptr]]]);
return 0;
}
A. -28 B. -21
C. -14 D. -35

Answer: Option A
Explaination:

-0[1[0[ptr]]]

=-1[0[ptr]][0] //From rule array[i]=i[array]
=-0[ptr][1][0]
=-ptr [0] [1] [0]
=-*ptr [0] [1] //From rule array[i]=*(array+i)
=-*(&array) [0] [1]
=-(&array) [0] [1][0]
=-(*&array)[1][0] //From rule *&p=p
=-array[1][0]
array[1][0] means 1*(3)+ 0 = 3rd element of array starting from zero i.e. 28



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