C - Operators - Discussion

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Q.

What will be output when you will execute following c code?

#include
int main(){
char a=250;
int expr;
expr= a+ !a + ~a + ++a;
printf("%d",expr);
return 0;
}
A. 249 B. 250
C. 0 D. -6

Answer: Option D
Explaination:

 


205 is beyond the range of signed char. Its corresponding cyclic value is: 6 So, a = -6

Operator! , ~ and ++ have equal precedence. And it associative is right to left.
So, First ++ operator will perform the operation. So value a will -5
Now, Expr = -5 + !-5 + ~-5 + -5
= -5 + !-5 + 4 - 5
= -5 + 0 + 4 - 5
= -6


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