Arithmetic Aptitude - Problems On Age - Discussion

You Are Here :: Home > Arithmetic Aptitude > Problems On Age - Discussion

 
Q.

The age of father 10 years ago was thrice the age of his son. Ten years hence, the father’s age will be twice that of his son. The ratio of their present ages is ?                        


A. 5:2 B. 7:3
C. 9:2 D. 13:4

Answer: Option B
Explaination:

 


Let sons age 10 years ago = x.


Then, fathers age 10 years ago = 3x.

2(x+ 10+ 10) = (3x + 10 + 10)so x = 20.

Ratio of their present ages = (3x + 10) : Cx + 10) 70: 30 = 7 :3.


Discussion

Your Comments Goes here...
NameDiscussion