Arithmetic Aptitude - Problems On Age - Discussion

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Q.

Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old as his son. Then the sum of the present ages of the son and the father is ?                         
A. 54 B. 72
C. 105 D. 108

Answer: Option D
Explaination:

 


Let the present ages of Father and Son be 2x years and x years respectively.


Then (2x-18)=3(x-18)

2x-18=3x-54

x=54-18

x=36.

Required sum = (2x+x)

=3x

=3x36

=108 years.


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